pydo.functions.get_namespace()

Generated on 3 Aug 2026 from pydo version v0.40.0

Usage

client.functions.get_namespace(
    namespace_id="fn-xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx",
)
Returns JSONRaises HttpResponseError

Description

Gets the namespace details for the given namespace UUID. To get namespace details, send a GET request to /v2/functions/namespaces/{namespace_id} with no parameters.

Parameters

namespace_id string required

The ID of the namespace to be managed.

Request Sample

Show Request Sample
import os
from pydo import Client

client = Client(token=os.environ.get("DIGITALOCEAN_TOKEN"))

resp = client.functions.get_namespace(namespace_id="aff93af3")

Response Example

Show Response Example
{
  "namespace": {
    "api_host": "https://api_host.io",
    "namespace": "fn-xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx",
    "created_at": "2022-09-14T04:16:45Z",
    "updated_at": "2022-09-14T04:16:45Z",
    "label": "my namespace",
    "region": "nyc1",
    "uuid": "xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx",
    "key": "d1zcd455h01mqjfs4s2eaewyejehi5f2uj4etqq3h7cera8iwkub6xg5of1wdde2"
  }
}

More Information

See /v2/functions/namespaces/{namespace_id} in the API reference for additional detail on responses, headers, parameters, and more.

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